$5^6\cdot4^6$
$-\frac{6x^2-3x}{x}+16x+12$
$4\left(-4\right)+2\left(-3\right)\left(4\right)-5\left(-4\right)\left(-2\right)^3$
$x^2+5x-1$
$-10=-5$
$y'=y^2$
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