$\left(2x^2\:+2\right)^{\frac{5}{2}}$
$\frac{9x^2+5}{3x}$
$\int\frac{x-9}{\left(2x-3\right)\left(x+3\right)^2}dx$
$\frac{d}{dz}z=\sqrt{x^2+y^2}$
$\frac{x}{5}-\frac{x}{2}=3+\frac{3x}{10}$
$-4x+1=-9x+16$
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