$\frac{x}{x-1}\ge\frac{1}{x-1}$
$6a^3-2a^2+8a$
$8y^2-12y+1=0$
$16x^4-9y^2$
$-3\left(-2x-8\right)$
$\lim_{a\to1}\frac{\left(x+a\right)^3-x^3}{a}$
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