$\frac{dy}{dx}=\frac{ycosx}{y^2-1}$
$\frac{x^2-13x+39}{x-6}$
$\left(5z\:-7\right)\:\left(5y\:-12\right)\:$
$\int\left(\frac{xe^2}{\left(1+2x\right)^2}\right)dx$
$-2+3\:-3.x^2\:+\:4.x^3$
$x=\frac{1}{\left(y-3y^2+6\right)^2}$
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