$\frac{dy}{dx}=y^2+36$
$\frac{\left(x+3\right)}{2-x}<2$
$\frac{6x-36}{5x^2-180}$
$\int-e^{-4x}\cdot\cos e^xdx$
$d^2-14+49$
$x^2+3x-6=0$
$\int\left(\frac{\left(e^{5x}\right)}{e^{5x}-5}\right)dx$
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