$3.\cos\left(x\right)=3$
$\left(2m^3+3m-5m^2\right)-4m$
$\left(3a+1\right)\left(1-3a\right)=1-9a^{2}$
$8m+3-2-10+9m$
$x^3-8+2x^2-4x^2+6x-4+2x-3x^3+5x^2+6x^3$
$\frac{x-11}{10}=\frac{x-10}{8}$
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