$\lim_{x\to0}\left(\frac{\sqrt{x}}{\sqrt{x+1}}\right)$

$\int_1^{\infty}\left(\frac{x\ln\left(x\right)}{\left(1+x^2\right)^2}\right)dx$

$\left(4\cdot\left(-1\right)-\left(3-7\right)\right)$

$\int\frac{x-4}{\left(x+1\right)\left(x-3\right)}dx$

$-8=11$

$3x+12y-2y+15x+5y$

$\frac{a}{a+1}-1$