3 ln 4 = 2 ln x3\:ln\:4\:=\:2\:ln\:x3ln4=2lnx
ln (6x+4)5ln\:\left(6x+4\right)^5ln(6x+4)5
(3y+7)(−4y)\left(3y+7\right)\left(-4y\right)(3y+7)(−4y)
(2x3−2x2−3x+3)x−1\frac{\left(2x^3-2x^2-3x+3\right)}{x-1}x−1(2x3−2x2−3x+3)
x+2y+x+2x + 2y + x + 2x+2y+x+2\:\:x+2y+x+2x\:+\:2y\:+\:x\:+\:2x+2y+x+2x+2y+x+2x+2y+x+2x+2y+x+2
20x4−5x2−10x2+15x−5x\frac{20x^4-5x^2-10x^2+15x}{-5x}−5x20x4−5x2−10x2+15x
∫x4+x3+xx2+x−2dx\int\frac{x^4+x^3+x}{x^2+x-2}dx∫x2+x−2x4+x3+xdx
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