$\lim_{x\to1}\left(\frac{\ln\left(x\right)}{3^{ln\left(x\right)}-x}\right)$
$x^2\frac{du}{dx}+u^2=0$
$m^2-1.4m+0.49$
$0=\left(xz+9\right)$
$\frac{5x}{y}-\frac{7}{8y}$
$-4\cdot9+7$
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