$\lim_{x\to2}\left(\frac{\left(4x-2\right)\left(x-3\right)}{\left(x^2-4x\right)\left(x-2\right)}\right)$
$2x+\sqrt{x+3}=4$
$\frac{3x^4+7x^3-3x^2+10x-19}{3x-2}$
$9u^2+30u+25$
$\frac{3x^2+3x}{x^2-9}$
$12^2+12x$
$\frac{y}{y+xy}$
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