$-6\left(-7\right)-3$
$\left(e^{\cdot}+1\right)^2$
$tan\left(x+\frac{3\pi\:}{4}\right)=\frac{\left(tanx-1\right)}{tanx+1}$
$5-3x^2\:para\:x=-3$
$\int\frac{2}{\left(x^3\right)}dx$
$\left(\:x^2\:+\:3x\right)^5$
$36x^3+18x^2-4x$
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