Factor the expression 5+20c20c^2

 Exercise

$5+20c+20c^2$

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Factor the polynomial $5+20c+20c^2$ by it's greatest common factor (GCF): $5$

$5\left(1+4c+4c^2\right)$

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The trinomial $\left(1+4c+4c^2\right)$ is a perfect square trinomial, because it's discriminant is equal to zero

$\Delta=b^2-4ac=4^2-4\left(4\right)\left(1\right) = 0$

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Using the perfect square trinomial formula

$a^2+2ab+b^2=(a+b)^2,\:where\:a=\sqrt{4c^2}\:and\:b=\sqrt{1}$

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Factoring the perfect square trinomial

$5\left(2c+1\right)^{2}$

$5\left(2c+1\right)^{2}$

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