$$\sin^2\left(x\right)\tan^2\left(x\right)=\tan^2\left(x\right)$$

$$\frac{d}{dq}\left(\frac{40}{ln\left(q+2\right)}\right)$$

$$\int23\left(t-4\right)^5\:dt$$

$$\frac{dy}{dx}^2=3x$$

$$\frac{x}{3}+8>12$$

$$-120+3\left(4-5\right)+8-12\:\left(7-3\right)$$