$\int\left(4-y^3\right)^2\:dy$
$y=\left(t+8\right)^2+\left(t+2\right)$
$\:-\left(8\:-\:12\right)\:-\:\left(2\:-\:5\right)\:$
$4x^2+44x+96$
$x^2+90x+2025$
$x^2-11x=1$
$\frac{1-\sin\:\left(x\right)^6}{\cos\left(x\right)^6}$
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