$$\frac{\left(1-sin^2x\right)}{sinx+1}$$

$$\frac{16c^4-81}{2c+3}$$

$$\frac{\left(40\cdot\sqrt{6}\right)}{2}$$

$$\frac{d}{dx}\left(\frac{5}{4}\right)\left(x^5-4x^3+5\right)^8$$

$$10x-6>56$$

$$67.5+78.9+.83+567.9$$