$\left(x+\frac{5}{6}\right)^2=\frac{169}{36}$
$\sqrt{x^2+14x+49}=8$
$x^4-x^2+2x+2$
$4^3+5\cdot4-1$
$\frac{8}{4}+\frac{6}{3}+c$
$\left(xy^2+xy^3\right)$
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