$x^3+40x^2$
$y'\:=\:x^2\:secy$
$2\left(2x^2\right)\left(-xy\right)$
$50x^3+40x^2+8x$
$\lim_{x\to1}\frac{x^2+x-2}{x^2-3x+2}$
$2\sin\left(60\right)\cdot\tan\left(30\right)$
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