$\sqrt[3]{4x^6y^3}$
$2x+x+3+6x$
$14\:=\:\frac{n}{2}\:+\:10$
$\left(8x-8\right)\left(8x+8\right)$
$4-20+8\cdot\left(-2\right)-5\cdot\left(-10\right)$
$\frac{x^3-6x^2-5x-2}{x-1}$
$\lim_{x\to\infty}\left(\frac{3x^2-x}{x+2}\right)$
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