$\frac{\left(2x+9x\right)^4}{\left(7x^3+6x\right)^2}$
$\left(-3x+9\right)-\left(-2x^2+6x\right)$
$\left(4z-1\right)\left(2z+5\right)$
$\int\tan^2\left(\frac{5x}{3}\right)x\:sec^4\left(\frac{5x}{3}\right)dx$
$5m^2+7m+15$
$\frac{d}{dx}\left(y+x^2\left(y\right)^4=18\right)$
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