5x+3x\frac{5x+3}{x}x5x+3
limx→3(x3−6x2+9x2−9)\lim_{x\to3}\left(\frac{x^3-6x^2+9}{x^2-9}\right)x→3lim(x2−9x3−6x2+9)
y+7+4(y+2)y+7+4\left(y+2\right)y+7+4(y+2)
(3x2−2y=20)\left(3x^2-2y=20\right)(3x2−2y=20)
limx→0(cos(2x))3x\lim_{x\to0}\left(\cos\left(2x\right)\right)\frac{3}{x}x→0lim(cos(2x))x3
x3y6−216y9x^3y^6-216y^9x3y6−216y9
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