$\lim_{x\to0}\left(\frac{1}{x}-\frac{2}{\sin\left(2x\right)}\right)$
$x^2+19x+12=\left(x+3\right)\left(x+4\right)$
$\left(y^3-1\right)\left(y^3+7\right)$
$6wz+8z+2+3wz$
$f\left(x\right)=in\left(\sqrt{x+1}\right)$
$x^4+2x^3-9x^2-2x+8$
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