$96-48mn^2+144$
$\int_0^1\left(x^4e^{-x}\right)dx$
$\left(\frac{2}{\sqrt{1-y^2}}\right)\frac{dy}{dx}=\left(\frac{1}{\sqrt{x}}\right)$
$3x^2+27x-16y+48=0$
$\int\tan^3\left(12x\right)\sec^3\left(12x\right)\:dx$
$-6\left(4x^3+2x\right)^4$
$\frac{-12x^3y^5}{3xy^3}$
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