$\frac{m^2-5^2}{m+5}$

$\lim_{x\to1}3$

$\frac{125xy^3}{x^4y^8}$

$6^0\cdot6^3$

$\lim_{x\to\frac{\pi}{2}}\left(\frac{1}{5cos\left(-7x\right)sec\left(5x\right)}\right)$

$\:\frac{dy}{dx}\:+\:\frac{2}{x}\:=\:\frac{\cos\left(x\right)}{x^2}$