Simplify the trigonometric expression 6cos(49w)sin(19w)

 Exercise

$6cos\left(49w\right)sin\left(19w\right)$

 

Apply the trigonometric identity: $\sin\left(x\right)\cos\left(y\right)$$=\frac{\sin\left(x+y\right)+\sin\left(x-y\right)}{2}$

$\frac{6\left(\sin\left(68w\right)+\sin\left(-30w\right)\right)}{2}$

 

Take $\frac{6}{2}$ out of the fraction

$3\left(\sin\left(68w\right)+\sin\left(-30w\right)\right)$

 

Use the odd-even identity $\sin(-\theta)=-\sin(\theta)$

$3\left(\sin\left(68w\right)-\sin\left(30w\right)\right)$

 

Multiply the single term $3$ by each term of the polynomial $\left(\sin\left(68w\right)-\sin\left(30w\right)\right)$

$3\sin\left(68w\right)-3\sin\left(30w\right)$

$3\sin\left(68w\right)-3\sin\left(30w\right)$

 Try other ways to solve this exercise

Can't find a method? Tell us so we can add it.