dydx=(3x2−2xy+3y2)(4xy)\frac{dy}{dx}=\frac{\left(3x^2-2xy+3y^2\right)}{\left(4xy\right)}dxdy=(4xy)(3x2−2xy+3y2)
−2x+7(x−1)\frac{-2}{x}+\frac{7}{\left(x-1\right)}x−2+(x−1)7
(5x + y2)3\left(5x\:+\:y^2\right)^3(5x+y2)3
(x−6x2−9)+(3x2+2x+1)\left(x-6x^{2}-9\right)+\left(3x^{2}+2x+1\right)(x−6x2−9)+(3x2+2x+1)
(2x+1)(2)−8<=(2x−1)(2)\left(2x+1\right)^{\left(2\right)}-8<=\left(2x-1\right)^{\left(2\right)}(2x+1)(2)−8<=(2x−1)(2)
(−19+25−31)⋅(−5−8)\left(-19+25-31\right)\cdot\left(-5-8\right)(−19+25−31)⋅(−5−8)
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