$a.a^{\frac{1}{4}}$
$-4.8x^2+498x-800;\:x=26$
$6x^2y^2+4xy^3y'\:=0$
$\frac{x^3-4}{x^2+8}$
$\frac{3}{5}\left(x+\frac{7}{8}\right)-\frac{5}{2}>-\:\frac{3}{2}$
$\frac{d}{dx}\left(sin\left(xy\right)=6x+5\right)$
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