$\left(\frac{3^5}{3}\right)^2$
$\sin\left(x\right)^2\cos\left(x\right)^2=\frac{1-cos\left(4x\right)}{8}$
$\int_0^{\pi}\left(3+\cos\left(x\right)\right)\sin\left(x\right)dx$
$16=-2x$
$\frac{x^5-4x^3+x-1}{x^2-1}$
$\left(3u^4-18u^3\right)\left(u-2\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!