$2y''+12y'+18y=0$
$\left(m^3-a\right)\left(m^3-3\right)$
$-10+40\cdot3$
$\sqrt{64x^6y^{12}}$
$\left(16x^{12}\right)\frac{1}{4}$
$\left(3x^2+2x\right)\left(3x^2-x\right)$
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