$sin\left(x\right)\left(1+tan^2\left(x\right)\right)$
$y=\frac{-x^2}{2}+8x$
$\int\left(\sin3.1416\right)dx$
$\lim_{x\to\frac{\pi}{2}}\left(\frac{6x-3\pi}{cos\left(2\pi-x\right)}\right)$
$3\sqrt{3}+6\sqrt{3}$
$-3g\:+\:2f,\:para\:g=\:-1\:y\:f=\:-\:5$
$2.2^3-2^2+6$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!