2r2+r−4=02r^2+r-4=02r2+r−4=0
∫(2x3+6)3x2dx\int\left(2x^3+6\right)^3x^2dx∫(2x3+6)3x2dx
4x2−10xy+6y4x^2-10xy+6y4x2−10xy+6y
2x+1=15−2(7−x)2x+1=15-2\left(7-x\right)2x+1=15−2(7−x)
∫(1tan2 x)dx\int\left(\frac{1}{tan^2\:x}\right)dx∫(tan2x1)dx
(−25)(−4)(−8)(−5)(−16)\frac{\left(-25\right)\left(-4\right)\left(-8\right)}{\left(-5\right)\left(-16\right)}(−5)(−16)(−25)(−4)(−8)
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