$\log_x\left(10\right)=0.5$
$\frac{3^2\:-\:x^2}{3+x}$
$\left(2x^3-3x^2+4x-2\right)-\left(x^4-x^3+4\right)+\left(3x^2-5x+5\right)$
$6x^2-60x+24=0$
$2.4+\left(-2.73\right)+\left(-5.09\right)$
$\left(7y-5\right)^2$
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