dydx=y2−9\frac{dy}{dx}=y^2-9dxdy=y2−9
dydx=y2−4\frac{dy}{dx}=y^2-4dxdy=y2−4
dydx=y−y2\frac{dy}{dx}=y-y^2dxdy=y−y2
dydx=y(y+2)\frac{dy}{dx}=y\left(y+2\right)dxdy=y(y+2)
dydx=(1+e−x)(y2−1)\frac{dy}{dx}=\left(1+e^{-x}\right)\left(y^2-1\right)dxdy=(1+e−x)(y2−1)
dydx=x2x−y\frac{dy}{dx}=\frac{x}{2x-y}dxdy=2x−yx
Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b
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