$x^2+\frac{4}{9}x$
$\lim_{x\to1}\left(\frac{ln\:x}{x^2-x}\right)$
$22xy^2+12x^4+8xy$
$12-9-2-o$
$2x-15>19$
$\left(\sin\left(x\right)+\cos\left(x\right)\right)\cdot\tan\left(x\right)-\sec\left(x\right)=\sin\left(x\right)-\cos\left(x\right)$
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