$6y\left(-4xy^2+3x\right)$
$\sqrt[4]{16x^{16}y^8}$
$\frac{2}{n}\left(6\right)$
$\frac{d}{dx}\:y^4-2y\:+\:3x^4=4x+y$
$x2\:+\:6\:x\:-\:7\:\:=\:0$
$5x\left(y^2+1\right)+\left(x+1\right)\left(y^2+1\right)$
$5x-47\ge\:5$
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