4y3⋅2x2y04y^3\cdot2x^2y^04y3⋅2x2y0
∫ 1(x+2)2+25dx\int\:\frac{1}{\sqrt{\left(x+2\right)^2+25}}dx∫(x+2)2+251dx
x+6x−1≤−5\frac{x+6}{x-1}\le-5x−1x+6≤−5
sin(80)cos(35)−cos(80)sin(35)\sin\left(80\right)\cos\left(35\right)-\cos\left(80\right)\sin\left(35\right)sin(80)cos(35)−cos(80)sin(35)
xy dx+xy2 dy =0xy\:dx+xy^2\:dy\:=0xydx+xy2dy=0
∫6sec2(x−9)dx\int6\sec^2\left(x-9\right)dx∫6sec2(x−9)dx
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