$3x^2-5x+6\cdot4x-2$
$\frac{3}{2-4x}\:,\:x=3$
$2^{5^0}$
$2x^2-7=4x$
$\frac{\sin^2\left(x\right)+2\sin\left(x\right)+1}{\cos^2\left(x\right)}$
$\frac{19x-38}{15}-\frac{5}{3}x=-\frac{4}{3}$
$\frac{d}{dx}\left(y^3-y-x\right)=0$
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