$-6\left(7x\:-8\right)$
$12x=60$
$3\left(x\right)\left(\frac{1}{2}\right)^2$
$\frac{d}{dx}tan^{-1}lnx+x^2$
$\left(-3a^2b\right)^2\left(-2ab^3\right)^4$
$6x^2+x$
$+\left(+12\right):\left(6-2\right)+11$
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