$\frac{dy}{dx}\left(\frac{xy^3}{sec\left(y\right)-1}=1+y^4\right)$
$9x^4+13x^2-23x+49\:para\:x=5$
$125x^6-8y^3$
$0.9867-0.995$
$3+2+2$
$14^{-1}\cdot14^1$
$5\log_m\left(6y+1\right)+\frac{1}{2}\log_m\left(y+5\right)$
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