$-6b+2+8$
$\left(3x-2\right)\left(3x-1\right)+2$
$\frac{2x^2+4x+5}{x-4}$
$\int_1^e\left(\frac{2x^2-5}{x}\right)dx$
$\left(-3x-25\right)-\left(-4x+2\right)+\left(2x+32\right)-\left(-8x+9\right)$
$-3a^2b^2-10^2b^2+13a^2b^2$
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