Exercise
$9x^5+3x\left(4x^4-3x^2\right)^2$
Step-by-step Solution
Learn how to solve problems step by step online. Expand the expression 9x^5+3x(4x^4-3x^2)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. The power of a product is equal to the product of it's factors raised to the same power. When multiplying exponents with same base we can add the exponents. Multiply the single term 3x by each term of the polynomial \left(16x^{8}-24x^{6}+\left(-3x^2\right)^2\right).
Expand the expression 9x^5+3x(4x^4-3x^2)^2
Final answer to the exercise
$9x^5+48x^{9}-72x^{7}+3\left(-3x^2\right)^2x$