$4+\left(-243\right)-4$
$\frac{1}{8a\left(3\right)}+8\left(3\right)$
$\lim_{x\to-\infty}\left(\frac{2e^x}{e^x-5}\right)$
$m2+19m-20$
$\lim_{x\to-4}\left(\frac{x^2-16}{x^3-64}\right)$
$8y^2z^4+2y^2z^4+5y^2z^4$
$\left(9x+6\right)\left(9x+3\right)$
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