y−3=−9y-3=-9y−3=−9
−1+cos2x−2sin2x-1+cos2x-2sin^2x−1+cos2x−2sin2x
y′=y+1x−1y'=\frac{y+1}{x-1}y′=x−1y+1
dydx=2x(cos(y)+2)\frac{dy}{dx}=\frac{2x}{\left(cos\left(y\right)+2\right)}dxdy=(cos(y)+2)2x
5−x−x=−15-x-x=-15−x−x=−1
(46)3\left(4^6\right)^3(46)3
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