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Solving: $\left(\arccos\left(\frac{\sqrt{2}}{2}\right)-\frac{\pi }{2}\right)\cos\left(\right)$
Solve instead: $cos\left[cos^{-1}\left(\frac{\sqrt{2}}{2}\right)-\frac{\pi}{2}\right]$

Exercise

$cos\left[cos^{-1}\left(\frac{\sqrt{2}}{2}\right)-\frac{\pi}{2}\right]$

Step-by-step Solution

1

Solve the product $\left(\arccos\left(\frac{\sqrt{2}}{2}\right)-\frac{\pi }{2}\right)\cos\left(\right)$

$\arccos\left(\frac{\sqrt{2}}{2}\right)\cos\left(\right)+\left(-\frac{\pi }{2}\right)\cos\left(\right)$

Final answer to the exercise

$\arccos\left(\frac{\sqrt{2}}{2}\right)\cos\left(\right)+\left(-\frac{\pi }{2}\right)\cos\left(\right)$

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Main Topic: Simplify Trigonometric Expressions

Simplification of trigonometric expressions consists of rewriting an expression with trigonometric functions in a simpler form. To perform this task, we usually use the most common trigonometric identities, and some algebra.

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