Solve the differential equation $\frac{dy}{dx}\cos\left(x\right)+y\sin\left(x\right)=1$

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Final answer to the problem

$y\cos\left(x\right)^{-1}=\ln\left|\frac{\tan\left(\frac{x}{2}\right)-1}{\tan\left(\frac{x}{2}\right)+1}\right|+\frac{-2\tan\left(\frac{x}{2}\right)}{\tan\left(\frac{x}{2}\right)^{2}-1}+2\ln\left|\frac{\tan\left(\frac{x}{2}\right)+1}{\sqrt{\tan\left(\frac{x}{2}\right)^{2}-1}}\right|+C_0$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
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Divide all the terms of the differential equation by $\cos\left(x\right)$

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$\frac{dy}{dx}\frac{\cos\left(x\right)}{\cos\left(x\right)}+\frac{y\sin\left(x\right)}{\cos\left(x\right)}=\frac{1}{\cos\left(x\right)}$

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Learn how to solve simplification of algebraic expressions problems step by step online. Solve the differential equation cos(x)dy/dx+sin(x)y=1. Divide all the terms of the differential equation by \cos\left(x\right). Simplifying. We can identify that the differential equation has the form: \frac{dy}{dx} + P(x)\cdot y(x) = Q(x), so we can classify it as a linear first order differential equation, where P(x)=\frac{\sin\left(x\right)}{\cos\left(x\right)} and Q(x)=\frac{1}{\cos\left(x\right)}. In order to solve the differential equation, the first step is to find the integrating factor \mu(x). To find \mu(x), we first need to calculate \int P(x)dx.

Final answer to the problem

$y\cos\left(x\right)^{-1}=\ln\left|\frac{\tan\left(\frac{x}{2}\right)-1}{\tan\left(\frac{x}{2}\right)+1}\right|+\frac{-2\tan\left(\frac{x}{2}\right)}{\tan\left(\frac{x}{2}\right)^{2}-1}+2\ln\left|\frac{\tan\left(\frac{x}{2}\right)+1}{\sqrt{\tan\left(\frac{x}{2}\right)^{2}-1}}\right|+C_0$

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Function Plot

Plotting: $\frac{dy}{dx}\cos\left(x\right)+y\sin\left(x\right)-1$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Simplification of algebraic expressions

The simplification of algebraic expressions consists in rewriting a long and complex expression in an equivalent, but much simpler expression. This simplification can be accomplished through the combined use of arithmetic and algebra rules.

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