$\lim_{x\to0}\left(\frac{\ln\left(e^x-1\right)}{\ln\left(x\right)}\right)$

$9m^3-36n^8$

$\int\frac{9x^2-16x+4}{x^3-3x^2+2x}dx$

$\left(8b^9\right)^2$

$\frac{1}{\csc\left(x\right)-\sin\left(x\right)}=\tan\left(x\right)\sec\left(x\right)$

$x^2-6x\ge\:-9$

$k^2-2k$