$\lim_{x\to0}\left(\frac{\sqrt{x}}{2^x}\right)$
$-7-4-1+2+5+8+11+14+17+20+23+26+29+31+34+43$
$25s^2+20st^3+4t^6$
$5y'-2e^{3x}y=0,\:y\left(0\right)=4$
$x^n-1\left(x^n+2\right)$
$5x+4<11-2x$
$\frac{d}{dx}\left(\arctan\left(\frac{2+x}{1-2x}\right)\right)$
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