$x^4+x^3+x^2+x$

$\left(4x^2-6b^3\right)^2$

$\left(3x+6\right)\left(3x+4\right)$

$\frac{\left(13^2\right)\:\left(13^4\right)}{\left(13^6\right)}$

$\frac{dy}{dx}=\frac{\left[y\left(x\right)-y\left(x\right)^2\right]}{x}$

$4x^2-13x+10$