$t^2-11t$
$\left(12u^2-8u-15\right)m^2$
$\frac{4c^3\left(-2\right)^3d^8}{2c^3\left(-2\right)d^2}$
$\frac{\frac{3x^2}{\left(x^2+1\right)^2}}{\frac{x}{\left(x^2+1\right)}}$
$\frac{\left(x'\right)}{1-4x}=\frac{1}{1-t^2}$
$\frac{1}{4}\cdot4-5$
$4j^2+9j^2$
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