$xy'=\frac{1}{2}y^2+y$

$6z+36$

$\left(132\left(\frac{1}{11}z^8-\frac{1}{12}\right)\right)^2$

$2\log\left(5\right)+\log\left(x+1\right)=1+\log\left(2x+7\right)$

$\frac{\sin^2\left(x\right)}{\cos^2\left(x\right)-\cos\left(x\right)}=1+\frac{1}{\cos\left(x\right)}$

$6x+7\le13$