$\frac{-5x+10}{x^3+6x+3x-1}$

$4\left(602-920\right)$

$\frac{1\:-tan^2x}{+tan^2}$

$4\left(\log_{10}\left(x\right)\right)^2+2\left(\log_{10}\left(y\right)\right)^2=9$

$\lim_{x\to0}\left(\frac{\sec\left(mx\right)-\sec\left(nx\right)}{x^2}\right)$

$-5\left(4-3\left(8-9\right)\left(7-3\right)+10\right)$